Zad 3
[tex] {ad}^{2} = {2}^{2} + {5}^{2} = 29[/tex]
[tex]ad = \sqrt{29} [/tex]
Ob=5+5+√29+√29=10+2√29
[tex] {ab}^{2} = {1}^{2} + {4}^{2} = 17[/tex]
[tex]ab = \sqrt{17} [/tex]
Ob=5+3+√17+√17=8+2√17
[tex] {ab}^{2} = {3}^{2} + {2}^{2} = 13[/tex]
[tex]ab = \sqrt{13} [/tex]
Ob=4•√13=4√13
Zad 4
[tex]xp = \frac{ - 3 + 1}{2} = \frac{ - 2}{2} = - 1[/tex]
[tex]yp = \frac{13 + 17}{2} = \frac{30}{2} = 15[/tex]
[tex]xr = \frac{ - 3 + ( - 1)}{2} = - 2[/tex]
[tex]yr = \frac{13 + 15}{2} = 14[/tex]
[tex]xs = \frac{ - 1 + 1}{2} = \frac{0}{2} = 0[/tex]
[tex]ys = \frac{15 + 17}{2} = 16[/tex]
Współrzędne punktu S, który dzieli odcinek PB na połowę