Odpowiedź:
[tex]\left \{ {{5(y+2)+x=3x+y} \atop {y+\frac{2,5}{5}=x+1}} \right.[/tex]
[tex]\left \{ {{5y+10+x-3x-y=0} \atop {5y+2,5=5x+5}} \right.[/tex]
[tex]\left \{ {{4y-2x=-10/*(-5)} \atop {5y-5x=2,5/*4}} \right.[/tex]
[tex]\left \{ {{-20y+10x=50} \atop {20y-20x=10}} \right.[/tex]
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-10x=60/:(-10)
x=-6
y+2,5/5=-6+1
y+0,5=-5
y=-5-0,5
y=-5,5
(x,y)=(-6 , -5,5)
[tex]\left \{ {{2(x+1)=3(y-1)+13} \atop {x-\frac{y}{3}=\frac{3x}{2}+\frac{3y}{4}+1/*12}} \right.[/tex]
[tex]\left \{ {{2x+2=3y-3+13} \atop {12x-4y=18x+9y+12}} \right.[/tex]
[tex]\left \{ {{2x-3y=8/*3} \atop {-6x-13y=12}} \right.[/tex]
[tex]\left \{ {{6x-9y=24} \atop {-6x-13y=12}} \right.[/tex]
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-22y=36/:(-22)
y=-³⁶/₂₂
y=-¹⁸/₁₁
2x-3*(-¹⁸/₁₁)=8
2x+⁵⁴/₁₁=8
2x=8-4¹⁰/₁₁
2x=³⁴/₁₁/:2
x=³⁴/₁₁*¹/₂
x=³⁴/₂₂=¹⁷/₁₁
x,y=(¹⁷/₁₁ , -¹⁸/₁₁)
Szczegółowe wyjaśnienie: