Temat:
MatematykaAutor:
whiskey10Utworzono:
1 rok temuOdpowiedź:
[tex]\left \{ {{y=1\frac{2}{3}} \atop {x=1\frac{8}{9}}} \right.[/tex]
Szczegółowe wyjaśnienie:
[tex]\left \{ {{3(x+1)-y-2=5} \atop {3x+2y=9}} \right. \\\left \{ {{3x+3-y=7} \atop {3x+2y=9}} \right. \\\left \{ {{-y=-3x+4\ |*(-1)} \atop {3x+2y=9}} \right. \\\left \{ {{y=3x-4} \atop {3x+2(3x-4)=9}} \right. \\\left \{ {{y=3x-4} \atop {3x+6x-8=9}} \right. \\\left \{ {{y=3x-4} \atop {9x=17\ |:9}} \right. \\\left \{ {{y=3x-4} \atop {x=\frac{17}{9}}} \right. \\\left \{ {{y=3*\frac{17}{9}-4} \atop {x=1\frac{8}{9}}} \right.[/tex]
[tex]\left \{ {{y=\frac{17}{3}-4} \atop {x=1\frac{8}{9}}} \right. \\\left \{ {{y=5\frac{2}{3}-4} \atop {x=1\frac{8}{9}}} \right. \\\left \{ {{y=1\frac{2}{3}} \atop {x=1\frac{8}{9}}} \right.[/tex]
Sprawdzenie:
[tex]3*(1\frac{8}{9}+1)-1\frac{2}{3}-2=5\\3*(\frac{17}{9}+\frac{9}{9})-1\frac{2}{3}-2=5\\3*\frac{26}{9}-1\frac{2}{3}-2=5\\\frac{26}{3}-\frac{5}{3}-2=5\\\frac{21}{3}-2=5\\7-2=5\\5=5\\\\3*1\frac{8}{9}+2*1\frac{2}{3}=9\\3*\frac{17}{9}+2*\frac{5}{3}=9\\\frac{17}{3}+\frac{10}{3}=9\\\frac{27}{3}=9\\9=9[/tex]
Autor:
budsssfp
Oceń odpowiedź:
6