Temat:
MatematykaAutor:
hannahUtworzono:
1 rok temu[tex]zad. 9 \ a)\\\\\sqrt[3]{2,7}*\sqrt[3]{80} \ \ \ \ \boxed {}\ \ \ 6\\\\obliczamy\ lewa\ strone\ stosujac\ zasade :\\\ \sqrt[n]{a} *\sqrt[n]{b}=\sqrt[n] {a*b}\\\\ L=\sqrt[3]{2,7}*\sqrt[3]{80}=\sqrt[3]{2,7*80}=\sqrt[3]{216}=6\\\\L=P\\\\\sqrt[3]{2,7}*\sqrt[3]{80} \ \ \ \ \boxed {=}\ \ \ 6[/tex]
[tex]b)\\\\\sqrt[3]{0,008}+\sqrt[3]{ \frac{27}{8}} \ \ \ \ \boxed {}\ \ \ 3\\\\obliczamy\ lewa\ strone \\\\ L=\sqrt[3]{0,008}+\sqrt[3]{ \frac{27}{8}}=0,2 +\frac{3}{2}=0,2+1,5=1,7\\\\L < P\\\\\\ \sqrt[3]{0,008}+\sqrt[3]{ \frac{27}{8}} \ \ \ \ \boxed { < }\ \ \ 3[/tex]
Autor:
shaynalecn
Oceń odpowiedź:
8