Odpowiedź:
Szczegółowe wyjaśnienie:
a) Pp = 6,25cm²
Pp = a²
a² = 6,25
a = [tex]\sqrt{6,25}[/tex]
a = 2,5 cm
V = a³ = (2,5)³ = 15,625 cm³
b) Sześcian ma 12 krawędzi, więc
a = [tex]\frac{36}{12}[/tex] = 3 cm
V = a³ = 3³ = 27 cm³
c) d = 8[tex]\sqrt{2}[/tex] dm
a[tex]\sqrt{2}[/tex] = 8[tex]\sqrt{2}[/tex] / [tex]\sqrt{2}[/tex]
a = 8 dm
V = a³ = 8³ = 512 dm³
d) D = 9m
D = a[tex]\sqrt{3}[/tex]
a[tex]\sqrt{3\\}[/tex] = 9
a = [tex]\frac{9 \sqrt{3} }{3}[/tex] = 3[tex]\sqrt{3}[/tex] m
V = a³ = (3[tex]\sqrt{3}[/tex])³ = 81[tex]\sqrt{3}[/tex] m³