Temat:
MatematykaAutor:
víctor65Utworzono:
1 rok temu[tex]zad.1\\\\\sqrt{16} -\sqrt{25} +\sqrt{0,01 } =\sqrt{4^{2} } -\sqrt{5^{2} } +\sqrt{\dfrac{1}{100} } =4-5+\sqrt{\dfrac{1^{2} }{10^{2} } }=-1+\dfrac{1}{10} =-\dfrac{10}{10}+\dfrac{1}{10}=-\dfrac{9}{10}=-0,9\\\\Odp.~~ B[/tex]
[tex]zad.2\\\\\sqrt{56\dfrac{1}{4} } =\sqrt{\dfrac{225}{4} } =\sqrt{\dfrac{15^{2} }{2^{2} } } =\dfrac{15}{2} =7\dfrac{1}{2} =7,5\\\\Najmniejsza~~liczba~~calkowita~~wieksza~~od~~7,5~~to~~8\\\\Odp:~~C[/tex]
[tex]zad.3\\\\\sqrt[3]{250}=\sqrt[3]{125\cdot 2} =\sqrt[3]{5^{3} \cdot 2} =\sqrt[3]{5^{3} } \cdot \sqrt[3]{2} =5\sqrt[3]{2} \\\\\sqrt[3]{2} \approx 1,26\\\\\sqrt[3]{250}\approx 5\cdot 1,26\approx 6,3\\\\Najwieksza~~liczba ~~calkowita~~mniejsza~~od ~~6,3~~to ~~6\\\\Odp:~~B[/tex]
[tex]zad.4\\\\a)\\\\\sqrt{0,0169} =\sqrt{\frac{169}{10000} } =\sqrt{\dfrac{13^{2} }{100^{2} } } =\frac{13}{100} =0,13\\\\b)\\\\\sqrt{2\dfrac{2}{49} } =\sqrt{\dfrac{100}{49} } =\sqrt{\dfrac{10^{2} }{7^{2} } } =\dfrac{10}{7} =1\dfrac{3}{7} \\\\c)\\\\\sqrt[3]{2\dfrac{10}{27} } =\sqrt[3]{\dfrac{64}{27} } =\sqrt[3]{\dfrac{4^{3} }{3^{3} } } =\dfrac{4}{3} =1\dfrac{1}{3}[/tex]
[tex]zad.5\\\\\sqrt{175} -\sqrt{63} -\sqrt{28} =\sqrt{25\cdot 7} -\sqrt{9\cdot 7} -\sqrt{4\cdot 7} =\sqrt{5^{2} \cdot 7} -\sqrt{3^{2} \cdot 7} -\sqrt{2^{2} \cdot 7} =5\sqrt{7} -3\sqrt{7}-2\sqrt{7} =5\sqrt{7} -5\sqrt{7} -5\sqrt{7} =0\\\\0\in C~~cbdu[/tex]
Autor:
red velvet03we
Oceń odpowiedź:
6