Temat:
MatematykaAutor:
ruthmoranUtworzono:
1 rok temuOdpowiedź:
Ad. 4/95
[tex]a) \: {9}^{10} = ({3}^{2})^{10} = {3}^{20} \\ {81}^{7} = ({3}^{4})^{7} = {3}^{28} \\ b) \: {4}^{7} = ({2}^{2})^{7} = {2}^{14} \\ {8}^{11} = ({2}^{4})^{11} = {2}^{44} \\ c) \: {125}^{4} = ({5}^{3})^{4} = {5}^{12} \\ {25}^{15} = ({5}^{2})^{15} = {5}^{30} \\ d) \: {10000}^{6} = ({10}^{4})^{6} = {10}^{24} \\ {100}^{9} = ({10}^{2})^{9} = {10}^{18} [/tex]
Autor:
leonunbc
Oceń odpowiedź:
7