[tex]f) \\\\\frac{x+2}3-\frac{x-4}4 > \frac{x-1}{12} /*12\\4(x+2)-3(x-4) > x-1\\4x+8-3x+12 > x-1\\x+20 > x-1\\20 > -1\\\text{Zawsze rownanie zawsze prawdziwe dla kazdego x w liczbach rzeczywistych}\\x\in R[/tex]
[tex]g)\\\\\frac{4-x}{5}-\frac{x+2}3 \geq \frac{2-8x}{15} /*15\\3(4-x)-5(x+2) \geq 2-8x\\12-3x-5x-10 \geq 2-8x\\-8x+2 \geq 2-8x\\2 \geq 2\\\\x\in R[/tex]
[tex]h) \\\\\frac{x-5}2-\frac{3-x}6 \leq \frac{x+4}3 /*6\\3(x-5)-(3-x) \leq 2(x+4)\\3x-15-3+x \leq 2x+8\\4x-18 \leq 2x+8\\4x-2x \leq 8+18\\2x \leq 26 /:2\\x \leq 13\\x\in(-\infty; 13 >[/tex]